Question

 


7) If one root of the quadratic equation 2x² + kx – 6 = 0 is 2, the value of k is *​

Answer 1

Answer:

K=-1

Step-by-step explanation:

2x^2+Kx-6=0.

2(2)^2+K2-6=0.

2×4+k2-6=0.

8+k2-6=0.

2+2k=0.

2k=-2.

k=-2/2.

k=-1

Answer 2

Answer:

$2x ^{2} + kx - 6 = 0 \\ 2(2) ^{2} + k \times 2 - 6 = 0 \\ 2 \times 4 + 2k - 6 = 0 \\ 8 - 6 + 2k = 0 \\ 2 + 2k = 0 \\ k = \frac{ - 2}{2} \\ k = - 1$

hope this will help you