Question

7. If one zero of the quadratic polynomial f(x) = 4x^2 - 8kx- 9 is negative of the other,
find the value of k.
8. If the sum of the zeros of the quadratic polynomial f(t) = kt^2+ 2t + 3k is equal to their
product, find the value of k
​

Answer 1

Answer:

X+1=0

X=-1

0=4*-1^2-8*k*-1-9

0=4+8k-9

0=-5+8k

5=8k

5/8=k

Answer 2

Step-by-step explanation:

Answer :-

→ k = 0 .

Step-by-step explanation :-

It is given that,

→ One zeros of the given polynomial is negative of the other .

Let one zero of the given polynomial be x .

Then, the other zero is -x .

•°• Sum of zeros = x + ( - x ) = 0 .

But, Sum of zeros = -( coefficient of x )/( coefficient of x² ) = - ( -8k )/4 .

==> 2k = 0 .

==> k = 0/2 .

•°• k = 0 .

Hence, it is solved.