Question

7. If p(x) = ax² – 3x + 7 b and 1, - 2 are zeroes of p(x),
then find the value of a and b.​

Answer 1

Answer: a= -3 and b= 6/7

Step-by-step explanation:

By using remainder theorem:

p(1) = a(1*1)-3*1+7b

= a+7b= 3. EQUATION 1

p(-2) = a(4)-3*-2+7b

4a+7b=-6. EQUATION 2

Now subtract EQ 1 from EQ 2

4a +7b-(a+7b)= -6-3

3a= -9

a=-3

Now put value of a in any EQ and find value of b