Question

7. If the angles of a pentagon are in the ratio 7:8:11: 13:15, find the angles.
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Answer 1

Answer:

sooooo easy

Step-by-step explanation:

please wait I solve this bro ok

Answer 2

ANSWER

From the question, it is given that, The angles of a pentagon are in the ratio 7: 8: 11: 13: 15

We know that, Sum of measures of all interior angles of polygons =(2n−4)×90

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Given, n=5

=((2×5)−4)×90

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=(10−4)×90

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=6×90

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=540

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Let us assume the angles of the pentagon be 7a,8a,11a,13a and 15a.

Then, 7a+8a+11a+13a+15a=540

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54a =540

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a =540/54

a =10

Therefore, the angles are 7a=7×10=70

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8a=8×10=80

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11a=11×10=110

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13a=13×10=130

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15a=15×10=150

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