Question

7. If the angles of a quadrilateral are xº, (2x +13)º,
(3x + 10), (x - 6), find x.​

Answer 1

QUESTION :-

If the angles of a quadrilateral are xº, (2x +13)º, (3x + 10), (x - 6), find x.

SOLUTION:-

We know that the four angles of any quadrilateral measure 360°.

=>Since, First angle + second angle + third angle + fourth angle = 360°.

[put, their values ]

=>x+2x+13+3x+10+x-6= 360°

=>7x + 17 = 360°

=>7x = (360-17)°

=>7x= 343°

=> x = 49°.

Hence, the value of x is 49°.

Answer 2

Given ,

The angles of a quadrilateral are x , (2x + 13) , (3x + 10) , and (x - 6)

We know that ,

The sum of all angles of quadrilateral is 360

Thus ,

$\sf \Rightarrow x + 2x +</p><p> 13 + 3x + 10 + x - 6 = 360 \\ \\\sf \Rightarrow 7x + 17 = 360 \\ \\ \sf \Rightarrow 7x = 343 \\ \\ \sf \Rightarrow x = \frac{343}{7} \\ \\ \sf \Rightarrow x = 49$

$\therefore \bold{ \underline{ \sf{The \: value \: of \: x \: is \: 49}}}$