Math, asked by preethigundam12, 3 months ago

7. If the diameter of a circle is increased by
100%. It's area is increased by
1) 100%
2) 200%
3) 300%
4) 400%​

Answers

Answered by ak77713
0

Answer:

May be the answer of this question is 100%.

Hope it's helpful to you.

According to my point of view this is the correct answer.

Answered by Diabolical
0

Answer:

The answer will be 300%.

Step-by-step explanation:

Let the initial diameter be x.

Now the radius (r) = x/2;

Then, area of circle = πr^2;

                                 = 22/7 * (x/2) * (x/2);

                                 = 11x^2/14;

After increasing 100% diameter;

New diameter = (100/100 * x) + x = 2x;

New radius = 2x/2 = x;

Thus, the area of circle with 100% increased diameter = π(x)(x);

                                                                                           = (22/7)*(x)^2;

                                                                                           = 22x^2/7;

Increase in area = (22x^2/7) - (11x^2/14);

                            = (44x^2 - 11x^2)/14;

                            = 33x^2/14;

Now, let the increased percent of area be y.

Thus, y% of (11x^2/14) = 33x^2/14;

          (y/100) * (11x^2/14) = 33x^2/14;

          y = (33x^2/14) / (11x^2/14) * 100;

          y = 3 * 100;

          y = 300;

Therefore the increased percent of area = 300%;

That's all.

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