Question

(7) If the magnitude of scalar and vector products of two vectors are 6 and 6
$\sqrt{3}$

respectively, then the angle between them is
A. 15°
B. 30°
C. 60°
D. 75°​

Answer 1

Hii Dude plz flw me on Instagram acc. - special_memer2

Answer:

B) 30°

Explanation:

Let θ be the angle between two vectors a & b then

The scalar product is given as

a.b=abcosθ =6√ 3 .....(1)

The magnitude of Vector product is given as

a*b=absinθ=6......(2)

The magnitude of Vector product is given as

Dividing (2) by (1) as follows

absinθ/abcosθ=6 √ 3/6

tanθ=1/ √ 3

θ=tan inverse 1/ √ 3

θ=30∘

Hope it helps.....

plz flw my insta acc. special_memer2 & if u can , then share my insta acc. I will be grateful to you