7.If the zeroes of the quadratic
polynomial are 2 and -3, then
quadratic equation is
O (A) x2+1x-6=0
O (B) x2+1x+6=0
O (C) x2-1X-6=0
O (D) x2-1x-6=0
Answers
Answer:
-x^2-14x-48=0
Simplifying
-1x2 + -14x + -48 = 0
Reorder the terms:
-48 + -14x + -1x2 = 0
Solving
-48 + -14x + -1x2 = 0
Solving for variable 'x'.
Factor out the Greatest Common Factor (GCF), '-1'.
-1(48 + 14x + x2) = 0
Factor a trinomial.
-1((8 + x)(6 + x)) = 0
Ignore the factor -1.
Subproblem 1
Set the factor '(8 + x)' equal to zero and attempt to solve:
Simplifying
8 + x = 0
Solving
8 + x = 0
Move all terms containing x to the left, all other terms to the right.
Add '-8' to each side of the equation.
8 + -8 + x = 0 + -8
Combine like terms: 8 + -8 = 0
0 + x = 0 + -8
x = 0 + -8
Combine like terms: 0 + -8 = -8
x = -8
Simplifying
x = -8
Subproblem 2
Set the factor '(6 + x)' equal to zero and attempt to solve:
Simplifying
6 + x = 0
Solving
6 + x = 0
Move all terms containing x to the left, all other terms to the right.
Add '-6' to each side of the equation.
6 + -6 + x = 0 + -6
Combine like terms: 6 + -6 = 0
0 + x = 0 + -6
x = 0 + -6
Combine like terms: 0 + -6 = -6
x = -6
Simplifying
x = -6
Solution
x = {-8, -6}