Question

7. If x = 1, y = 2 and z = 3, then verify:
23 + 13 + z3 – 3xyz = (x + y + z)(x2 + y2 + z2 - xy - yz – zx)​

Answer 1

Step-by-step explanation:

answer is 28

● only put value in x=1 ,y=2, z= 3

Answer 2

Step-by-step explanation:

23+13+9-12=(6)(12-2-6-3)

36+9-12=(6)(1)

24+9=6

33=6

not equval