7. In a A ABC, if 3 angle A = 4 angle B = 6 angle C, calculate the angles
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Answer:
Let 3/_A = 4/_B = 6/_C = x
/_A = x/3
/_B = x/4
/_C = x/6
We know,
/_A + /_B + /_C = 180
x/3 + x/4 + x/6 = 180
(4x + 3x + 2x)/12 = 180
9x = 180 × 12
x = 240
/_A = x/3 = 240/3 = 80°
/_B = x/4 = 240/4 = 60°
/_C = x/6 = 240/6 = 40°
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