Question

7. In A ABC, ZB = 90°, BC = 8 cm and
AC = 17 cm. BE is a median of the triangle
and M is the midpoint of BE. Find the area
of BMC​

Answer 1

$\sf \bf \huge {\boxed {\mathbb {QUESTION}}}$

In A ABC, ZB = 90°, BC = 8 cm and

AC = 17 cm. BE is a median of the triangle

and M is the midpoint of BE. Find the area

of BMC

$\sf \bf \huge {\boxed {\mathbb {ANSWER}}}$

∴BM=5 cm

$\sf \bf {\boxed {\mathbb {GIVEN}}}$

Given: △ABC, ∠B=90∘ and BM is median AC

$\sf \bf {\boxed {\mathbb {SOLUTION}}}$

By Apollonius Theorem,

AB2+BC2=2(BM2+MC2)

82+62=2(BM2+52)

64+36=2(BM2+25)

50=BM2+25

BM2=25

∴BM=5 cm

$\sf \bf \huge {\boxed {\mathbb {HOPE \:IT \:HELPS \:YOU}}}$

__________________________________________

Answer 2

Answer:

By Apollonius Theorem,

AB2+BC2=2(BM2+MC2)

82+62=2(BM2+52)

64+36=2(BM2+25)

50=BM2+25

BM2=25

∴BM=5 cm