7.
In a bag, there are 4 red balls, 5 green balls and 7 blue balls. One ball is picked up randomly. What is
the probability that it is neither red nor blue?
(A) 11/46
(B) 5/16
(C) 11/5
(D) None of these
Answers
Answered by
0
Answer:
option b 5/16 is correctly
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Answered by
4
Answer:
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Step-by-step explanation:
Red balls =4
Green balls =5
blue balls =7
total no of balls = 4 + 5 + 7 = 16
probability of red = no of favorable outcomes
------------------------------------------------
total no of outcomes
= 4 /16
= 1 / 4
probability of red = 1 by 4
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