Math, asked by ekamjeetvirk641, 4 months ago

7. In a game at a fete a pointer is spun. You win the amount of
money written in the sector where the pointer stops. Each sector
is equally likely. Work out the probability that you win
(a) no money
(b) 2 rupees
(d) 10rupees
(c) 6 rupees

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Answers

Answered by NitishKdhiran
7

Answer:

㋛︎㋛︎

Step-by-step explanation:

probability= favourable outcome/ total no. of outcome

a)no money

favourable outcome= 8

total no. of outcome=16

8/16= 1/2

1/2 is the probability of getting no money

b) 2 rupees

favourable outcome=4

total no. of outcome=16

4/16 = 1/4

1/4 is the probability of getting 2 rupees

c) 10 rupees

favourable outcome= 0

total no. of outcome = 16

0/16 = 0

so, getting 10 rupees is not possible in this situation

d) 6 rupees

favourable outcome= 0

total no. of outcome =16

0/16 = 0

so, getting 6 rupees is not possible in this situation as above

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