Question

7. In a three-digit number, the digit in the unit's place
is 75% of the digit in the ten's place. The digit in the
ten's place is greater than the digit in the hundred's
place by 1. If the sum of the digits in the ten's place
and the hundred's place is 15, what is the number?
(Bank P.O., 2006)​

Answer 1

Answer:

Step-by-step explanation:

Let the hundred's digit = x

Then, ten's digit = (x + 1)

Unit's digit :

=75% of (x+1)=34(x+1)

∴(x+1)+x=15⇔2x=14⇔x=7

So, hundred's digit = 7

Ten's digit = 8

Unit's digit :

=34(x+1)=34(7+1)=34(8)=6

Hence, required number = 786