Question

7. In ∆ ABC, AC=25cm, BC=7cm, AE=10cm.

find (i) the area of ∆ ABC

(ii) DB​

Answer 1

Answer:

Step-by-step explanation:

BC is the base and AE is the height of the triangle. Hence Area of triangle ABC is = 1/2 x height x base = 1/2 x 10 x 7 = 35 sq. cm.

DB is the altitude of triangle ABC. Base is AC = 25 cm. Hence height of triangle DB is given by 1/2 x height DB x base AC = 35 sq. cm

i.e. 1/2 x DB x 25 = 35 sq. cm.

25 DB = 70

DC = 70/25 = 2.8 cm

Answer 2

Answer:

Answer is totally correct and explained properly