Question

7. In ABC, the length of side BC is greater than the length of side AB by 3 cm
but is less than the length of side AC by 2 cm. If the perimeter of the triangle is
53 cm, find the length of the greatest side of ABC
1)16
2)18
3)20
4)21​

Answer 1

Answer:

20

Step-by-step explanation:

BC is greater than AB but less than AC, so AC is the greatest side. This is the one we want. Let x be this length (i.e. the length of AC).

Since BC is less than AC by 2, the length of BC is x-2.

Since BC is greater than AB by 3, the side AB is 3 less than BC, so AB has length (x-2)-3 = x-5.

The perimeter is the sum of all three side lengths, which is then

x + (x-2) + (x-5) = 3x - 7.

We're told the perimeter is 53 though, so

3x - 7 = 53

=> 3x = 60

=> x = 20.

Answer 2

Answer:

20 Answer

Step-by-step explanation:

The Perimeter is 53 is Length

So then Hold the method to The traingle

( x -2 ) + ( x - 5) = -3 -7

3X -7 =53

3X = 60

X = 60 /3

X = 20

Therefore ,the answer is 20