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7. In an isosceles triangle, the length of each of congruent sides is 10 cm and the length of base is 12 cm. Find the
length of altitude AD.
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Perimeter of the isosceles triangle = 13+13+10 = 36 cm
Thus, s = 36/2 = 18cm.
Area of triangle = [18(18–13)(18–13)(18–10)}^0.5 = [18*5*5*8]^0.5 = 60 sq cm.
Altitude of the triangle = 60*2/10 = 12 cm.
Since the centroid is two thirds of the way from the vertex to any base, the answer to your question is 8 cm.
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