Question

7. In Fig. 13.27, ABC is an equilateral triangle
and AD is perpendicular to BC. Prove that
AADB = AADC in three different ways.
Fig. 13.27​

Answer 1

$\bold\ANSWER$

In △ADB and △ADC

AB=AC (given)

AD=AD (common side)

∠ADB=∠ADC=90

∘

(AsAD⊥BC)

∴△ADB≅△ADC by RHS property.

Answer 2

Step-by-step explanation:

1) AB = AC (GIVEN)

ANGLE BDA = ANGLE CDA (90°)

BD= DC (GIVEN)

∆ ADB ~=∆ADC(RHS)