Question

7. In fig. 25.29, PQRS is
a rhombus . SOLVE TO BE BRAINLIEST ​

Answer 1

Answer:

angle PQO = 38° and angle PSR = 96°

Step-by-step explanation:

( i ) In ∆POQ : angle POQ = 90° ( since, diagonals of rhombus are perpendicular bisectors)

Therefore, 180° = angle POQ + angle QPO + angle PQO which results as angle PQO = 38°.

( ii ) In ∆ PQR : angle PQO = angle RQO = 38° ( since diagonals bisects angles of llgm in two equal angles )

Therefore, angle PSR = angle PQR = 2 x angle PQO = 2 x 38° = 96° ( since, opposite angles of llgm are always equal ).

Hence, angle PQO = 38° and angle PSR = 96°