Question

7)
In figure , O is the centre of the circle.
Seg AB, seg AC are tangent segments.
Radius of the circle is r and l(AB) = r,
Prove that,DABOC is a square.





here's a figure​

Answer 1

Step-by-step explanation:

angle ABO = angle ACO= 90° ( tangent at any point of circle is perpendicular to radius through point of contact)

given that AB = r (OB/OC)

AB = AC ( length of 2 tangents drawn from an external point to a circle are equal )

so AB = AC = OC = OD

and also angle ABO = angle ACO = 90

Therefore ABOC is a square