Physics, asked by kamblejoyti24, 17 days ago

7. In isobaric process
(a) ΔΡ= 0, ΔΤ≠0
(b) ΔΡ= 0, ΔΤ=0
(c) ΔΡ≠ 0, ΔΤ=0
(d) ΔΡ≠0, ΔΤ≠0
Other: :???​

Answers

Answered by santoshseth2410
1

Answer:

the first option i.e., option (a)

∆P=0, ∆T ≠0

Explanation:

Becoz the pressure is constant in isobaric. process

so, change in pressure is zero.

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