7. In isobaric process
(a) ΔΡ= 0, ΔΤ≠0
(b) ΔΡ= 0, ΔΤ=0
(c) ΔΡ≠ 0, ΔΤ=0
(d) ΔΡ≠0, ΔΤ≠0
Other: :???
Answers
Answered by
1
Answer:
the first option i.e., option (a)
∆P=0, ∆T ≠0
Explanation:
Becoz the pressure is constant in isobaric. process
so, change in pressure is zero.
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