Question

7. In parallelogram ABCD, BC = 7.5 cm and
CD = 10 cm. ANI BC and CM I AB. If
altitude AN= 8 cm, find altitude CM.​

Answer 1

$\Huge\tt{{\color{purple}{{\underline{AN}}}}{\color{orchid}{{\underline{SW}}}}{\pink{{\underline{ER}}}}{\color{lightpink}{:-}}}$

• The altitude CM=6 cm

$\huge\Large\underline\mathtt\pink{Step \:By\:Step \:Explanation:-}$

In parallelogram ABCD

AD=BC=7.5 cm

AB=CD=10 cm

AN=8 cm

Area of parallelogram= Base×height

Using the formula

Area of parallelogram ABCD=

BC × AN=7.5

BC×AN => 7.5×8=60cm²

Again, area of parallelogram ABCD=AB CM=10 CMAB×CM=10×CM

60=10×CM

CM=60/10 = 6 cm

CM = 6cm

Hence, the altitude CM=6 cm

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#Learns more:

https://brainly.in/question/353970:Answered by Laasya

Answer 2

Answer:

In parallelogram ABCD

AD=BC=7.5 cm

AB=CD=10 cm

AN=8 cm

Area of parallelogram= Base×height

Using the formula

Area of parallelogram ABCD=

BC × AN=7.5

BC×AN => 7.5×8=60cm²

Again, area of parallelogram ABCD=AB CM=10 CMAB×CM=10×CM

60=10×CM

CM=60/10 = 6 cm

CM = 6cm

Hence, the altitude CM=6 cm