Question

7. In quadrilateral ABCD, BC is the diagonal, DO is perpendicular to BC, and CX is perpendicula
AB = 25 cm, BC = 16 cm, CX = 8 cm, and DO = 5 cm, find the area of the quadrilateral.
А
Х
B
Th.
D
1.1.1. AR-20 am and A
-20 cm P is the midnoint of AD
is the​

Answer 1

Answer:

the area of quadrilateral sum of all the sides 25 + 16 + 8 + 5 centimeters is the answer of your question

Answer 2

The area of quadrilateral ABCD=140 square cm

Step-by-step explanation:

BC=16 cm

AB=25 cm

CX=8 cm

OD=5 cm

Area of triangle=$\frac{1}{2}\times base\times height$

Using the formula

Area of triangle ABC=$\frac{1}{2}\times AB\times CX=\frac{1}{2}\times 8\times 25=100 cm^2$

Area of triangle BCD=$\frac{1}{2}\times BC\times OD=\frac{1}{2}\times 16\times 5=40 cm^2$

Area of quadrilateral ABCD=Ar(ABC)+ar(BCD)=100+40=140 square cm

Hence, the area of quadrilateral ABCD=140 square cm

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