Question

7. In the adjoining figure, DE is a chord parallel
to diameter AC of the circle with centre 0. If
ZCBD = 60°, calculate ZCDE.​

Answer 1

Answer:

I hope this is helpful for u

Answer 2

Answer:

ANGLE CDE=30°

Step-by-step explanation:

<ADC=90° ( angles on semicircle is 90 degree )

<DAC=<DBC=60° ( angles on same segment are equal )

In ADC,

<ADC+<DAC+<ACD =180° ( angle sum property of a triangle )

=>60°+90°+<ACD=180°

•°•<ACD=180-150 i.e. 30°

<ACD=<CDE=30°( alternate interior angles )

HOPE THIS HELP YOU :)