Question

7. In the adjoining figure, the diagonals AC and BD of parallelogram
ABCD intersect at O. If angle OBC = 36°, angle ODC = 28° and angle AOD = 64°;
find the measure of (i) angle OAD (ii) angle OCD.​

Answer 1

Answer:

¡SIDES OF A PARALLELOGRAM ARE PARALLEl

OA=OD(DIAGONAL OF A PARALLELOGRAM BISECT EACH OTHER)

THUS

ANGLE OAD=ODA (ANGLES OPP. TO EQUAL SIDES )

so angle OAD + angle DOA+ ANGLE ODA =180

angle 2OAD+ 64°=180°

2OAD=180-64

2OAD=116

OAD,=116/2

OAD =58°

¡¡ OC=OD ( DIAGONAL OF A PARALLELOGRAM BISECT EACH OTHER)

THUS

ANGLE ODC=ANGLE OCD=28°(ANGLES OPP. TO EQUAL SIDES)

PLEASE MARK BRAINLIEST