7. In the circuit shown in Fig. 14.5, if the diode forward voltage drop is 0.3 V, the voltage difference between A and B is (a) 1.3 V (b) 2.3 V (c) 0 (d) 0.5 V
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Explanation:
let V be the potential difference between A and B, then V - 0.3 = (5 +5) x 103 x (0.2 x 10-3) =2 or V = 2 + 0.3 = 2.3 V
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