Question

7. In the circuit shown in figure, if ammeter and voltmeter
are ideal, then the power consumed in 922 resistor
will be
9Ω
WWWWW
6Ω
ΜΜΜΛΛΑ
20Ω
ν
10 Ω
(A
30Ω
30V
(1) 3.33 W
(2) 4 W
(4) 500 W
(3) 1.44 W​

Answer 1

Answer:

I=Rnet30

Rnet=20+5=25

It=25−30=56A

voltage at 20Ω=56×20=24 V

all parallely connected resistors

v=6 V

R=9+6=15 Ω

RV=I through 9 & 6 Ω resistor

156=I

Power consumed by 9 Ω=I2R

15×156×6×9=1.4 W

hope you understood buddy