Question

7. In the diagram, ABCD and EFGH are rectangles with
AB = 10 cm, BC= 7 cm, EP= 7 cm and FG=4 cm, all
figures accurate to the nearest cm.
Find the largest possible value of the shaded area.
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Answer 1

Answer:

Area of ABCD = AB × BC. = 10×7 = 70 cm square

area of EFGH = EF × FG. = 7 ×4 = 28 cm square

now area of shaded portion = area of ABCD - area of EFGH. = 70-28 = 42 cm square

Answer 2

Step-by-step explanation:

1. AB=10cm BC=7cm
2. area of ABCD= l×b =10×7= 70.
3. EF=7cm FG=4cm
4. area of EFGH=l×b= 7×4=28
5. shaded part is ABCD _EFGH= 70_28 =42