Question

7. In the figure 10.13, ZA = 75° and CE || AB. If ZECD = 40°, find the other two angle of the triangle ABC. A E 1 75° 40° C В D Fig. 10.13
I give you 50 points​

Answer 1

Answer:

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Answer 2

Answer:

as AB is parallel to CE

lambda*C = ECA = 75 { alternate interior angles }

ACD = 75 + 40 = 115

ACD=BAC+ - C * BA (exterior angle}

115 = 75 + CBA

CBA = 40

A + B + C = 180

75 + 40 + C = 180

C = 180 + 115 = 65.

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