7. In the figure, AD = AE and AB = AC, prove that:
(i) DC = BE
(ii) ACD = ABE
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BE = DC & ∠ABE = ∠ACD
Step-by-step explanation:
refer attached figure :
in ΔADE
AD = AE
=> ∠ADE = ∠AED
=> ∠ADC = ∠AEB
in ΔABC
AB = AC
=> ∠ABC = ∠ACB
=> ∠ABE = ∠ACD
in ΔABE & ΔACD
AB = AC
∠ABE = ∠ACD
∠AEB = ∠ADC
=> ΔABE ≅ ΔACD
=> BE = DC
∠ABE = ∠ACD
QED
Proved
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