Question

7. In the figure, if angle
POQ = 130°. TP and TQ are tangents to a circle of centre 'O', then what is the
measure of angle PTO.
​

Answer 1

Answer:

70°

Step-by-step explanation:

Given, ∠POQ=110°

We know,

∠OPT=∠OQT=90°(Angle between the tangent and the radial line at the point of intersection of the tangent at the circle)

Now, in quadrilateral POQT

Sum of angles=360°

∠OPT+∠OQT+∠PTQ+∠POQ=360°

90°+90°+∠PTQ+110°=360°

∠PTQ=360°−290°

∠PTQ=70°

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