Question

7) In the figure, N is the midpoint of the side LM.O divides the line KN in the ratio 2:1 from K. Area of triangle KLM is 60 square centimetres. a) Find the area of triangle KLN. b) Find the area of triangle KOM. c) Find the area of triangle LOM.​

Answer 1

answer:

is given that L, M and N are mid-point of the side PQ, PR and QR respectively of ΔPQR. If PQ=4.4cm, QR=5.6cm and PR=4.8 cm.

Since, L, M and N are mid-point of the side PQ, PR and QR respectively of ΔPQR., therefore

LM=\frac{1}{2}(QR)LM=

2

1

(QR)

LM=\frac{1}{2}(5.6)=2.8cmLM=

2

1

(5.6)=2.8cm ,

LN=\frac{1}{2}(PR)=\frac{1}{2}(4.8)=2.4cmLN=

2

1

(PR)=

2

1

(4.8)=2.4cm

and MN=\frac{1}{2}(PQ)=\frac{1}{2}(4.4)=2.2cmMN=

2

1

(PQ)=

2

1

(4.4)=2.2cm

Thus, the perimeter of ΔLMN will be given as:

P=LM+LN+MNP=LM+LN+MN

P=2.8+2.4+2.2P=2.8+2.4+2.2

P=7.4 cmP=7.4cm

Therefore, the perimeter of ΔLMN is 7.4 cm.