Question

7. In the following figure, FD and AE are parallel to each other and angle ABC =
49. Then ABC + DCB is equal to
8. The radius of a circular box is 10 cm. What should be the length of the
tape required to wrap once around the pipe?

​

Answer 1

Question 7) In the following figure, FD and AE are parallel to each other and ∠ABC = 49° . Then ∠ABC + ∠DCB is equal to ?

Solution :-

Given that, FD || AE,

Therefore,

→ ∠ABC = ∠DCB . { Alternate interior Angle. }

So,

→ ∠ABC + ∠DCB = 49° + 49° = 98° . (Ans.)

______________________

Question 8) The radius of a circular box is 10 cm. What should be the length of the tape required to wrap once around the pipe ?

Solution :-

→ Length of the tape required to wrap once around the pipe = Circumference of circle.

Given that,

→ Radius of circular box = 10cm.

So,

→ Circumference of circular box = 2 * π * radius = 2 * 3.14 * 10 = 62.8cm.

Hence, length of the tape required to wrap once around the pipe is 62.8cm.

_____________________

Answer 2

Answer:

mark as BRAINLEST ANSWER please

Step-by-step explanation:

mark as BRAINLEST ANSWER please