Question

7. In the given figure (13.48), ABCD is a parallelogram in which DAP = 20 . BAP = 40 and ABP = 80 . Find APD and BPC.​

Answer 1

Answer:

in a parallelogram opposite angles are same

DAB=DCB=20+40=60

in a parallelogram the sum of all angles is 360

D+A+B+C=360

D=B

so we can write

60+60+2B=360

2B=360-120=240

B=120=D

B=CBP+PBA=120

CBP=120-80=40

in triangle PCB the sum of angles are 180

CPB+PBC+PCB=180

CPB=180-(40+60)=80

similarly,

in triangle APD

ADP+APD+DAP=180

120+APD+20=180

APD=180-140=40