7) In the given figure, if PA⊥AB, QB⊥AB and ΔOAP ≅ ΔOBQ, then
(1)AP=QP
(2)PA=OB
(3)OP=BQ
(4)OA=OQ
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Answer:
,
PA ⊥ AB, QB ⊥ AB and PA = QB
To prove,
ΔOAP = ΔOBQ
Is OA =OB?
Proof,
In ΔOAP and ΔOBQ
PA = QB (given)
∠POA = ∠QOB (vertically opposite angles)
∠OAP = ∠OBQ = 90o
From AAS congruence property,
ΔOAP ≅ ΔOBQ
Then,
OA = OB (corresponding parts of the congruent triangles)
Step-by-step explanation:
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