Physics, asked by shishirkesarwani10, 6 months ago

7.
In the two curves drawn between frictional
force f and applied force F for 2 bodies on
ground. Then correct statement is
fa
fa
40 N
20 N
se,
→F
►F
(A)
(B
2
(1) , > 0
(2) Coefficient of static friction may be more for (B)
(3) Coefficient of kinetic friction is same as
coefficient of static friction for both
(A) & (B)
(4) Coefficient of static friction will be more for (A)​

Attachments:

Answers

Answered by Anonymous
13

Answer:

F

►F

(A)

(B

2

(1) , > 0

(2) Coefficient of static friction may be more for (B)

(3) Coefficient of kinetic friction is same as

coefficient of static friction for both

(A) & (B)

(4) Coefficient

5 {6 \times \\  \\  \\  \\  \\ 3 \times  \times  \times  -  -  -  \times \frac{?}{?} }^{?}

Answered by sourasghotekar123
2

Answer:

(A) & (B)

Explanation:

Given:

force f and applied force F for 2 bodies on

Let:

f_{b}=u*(\frac{m}{2}+m)*g

=0.1+3mg/2=0.15mg

Now both blocks move together

f_{a} > =m_{a}\\f_{a} > =\frac{m}{2*\frac{3m}{2} }\\F=f_{a}+f_{b}                          

0.15mg+0.1mg=0.25mg

See more:

https://brainly.in/question/27553238

#SPJ2

Similar questions