Question

7. In triangle ABC, the bisectors of ZB and Z C intersect
at P. A line drawn through P and parallel to
BC intersects AB at X and AC at Y. Prove
that XY = XB + YC.​

Answer 1

Step-by-step explanation:

explained through diagram

Answer 2

Answer:

|_ABC & |_ACB meet at P in a Triangle ABC.

P||Q is parallel to BC

|_XPB = |_PBC (Alternate Angle) ---(1)

PB is a angular bisector, hence XBP=|_PBC ---(2)

and XB=XP ---(3)

Similarly, we can show that, YC=YP ---(4)

Add, Equation (3) and (4), we get XB+YC=XP=XY

HOPE YOU LEARN THIS

PLEASE GIVE ME 5 STAR AND BRAILLIANT ANSWER

AND ALSO FOLLOW ME