Question

7 into x cube by 4 =23 , what is the value of x?

Answer 1

$\frac{7 {x}^{3} }{4} = 23 \\ {7x}^{3} = 92 \\ {x}^{3} = 13.14 \\ x = 2.6$

Answer 2

Given equation is $\frac{7x^3}{4}=23$

To solve this equation for x, we need to isolate x using standard operations.

we can start by removing denominator.

4 is dividing so we will do opposite operation which is multiplication by 4 on both sides.

$\frac{7x^3}{4}*3=23*4$

$7x^3=92$

7 is multiplied on left side so we will do opposite operation which is division by 7 on both sides.

$\frac{7x^3}{7}=\frac{92}{7}$

$x^3=\frac{92}{7}$

Now we need to remove the cube from left side so let's take cube root of both sides

$x=\sqrt[3]{\frac{92}{7}}$

Hence final answer is $x=\sqrt[3]{\frac{92}{7}}$ which is approx x=2.35991627724.