Question

7. Isothermally and reversibly one mole of neon expand from 2 mºto 20 m3 and produce 831.4 J of work.
The temperature at which expansion takes place is (R= 8.314 JK 1 moll)
a) 434.2 K b) 4342 K
c) 43.42 K d) 316.42 K​

Answer 1

Answer:

w = -nRT ln (Vf/ Vi)

w = -(1 mol)(8.314 J K-1 mol-1) (300 K) ln (10 m3 / 5 m3) = -1728 J