Question

√7 ko Sankhya rekha per pradarshit kijiye

Answer 1

Answer:

follow the graphic methods

Answer 2

Answer:

Step-by-step explanation:

• Let us assume that  √7 is a rational number.
• Then it must in the form of p/q          [ ∵ q≠0]
• {p and q are co-prime number}
• √7=p/q
• squaring both sides
• 7 q^2=p^2     --------------------(1)
• p^2 is divisible by 7
• p is divisible by 7
• p=7 c     [∵ c is a positive integer] {squaring both sides}

   p^2 = 49 c^2-------------------(2)

substitute p^2 in equation (1) we get,

7 q^2=49 c^2

∴ Thus, q and p have a common factor of 7.

There is a contradiction.

As our assumption p and q are a co-prime

∵ But it has a common factor.

∴ So, that √7 is an irrational number.

HOPE THIS WILL HELPS:)

PLEASE MARK ME AS BRAINLIEST

PLEASE FOLLOW ME