Question

7. Land M are the red points of sides AB
DC respectively of parallelogram ABCD
Prove that gets DL and BM trise​

Answer 1

(-1) to the power odd is -1

-1 to the power even is 1

(-1) to the power 13 is -1 as 13 is odd..

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PLZZ MARK ME AS BRAINLIEST....

Answer 2

ǫᴜᴇsᴛɪᴏɴ -

L and M are the midpoints of sides AB and DC respectively of parallelogram ABCD. Prove that segments DL and BM trisect diagonal AC.

ɢɪᴠᴇɴ -

• L and M are the midpoints of sides AB and DC respectively.
• ABCD is a parallelogram.

ᴛᴏ ᴘʀᴏᴠᴇ -

DL and BM trisect diagonal AC.

ᴘʀᴏᴏғ -

Since,

ABCD is a parallelogram.

∴ AB || DC [opposite sides of parallelogram are parallel and equal]

∴ AB/2 = DC/2

=> LB = DM.

∴ LBMD is a parallelogram [opposite sides of parallelogram are equal]

∴ LB || DM [opposite sides of parallelogram are parallel]

Now,

L is the midpoint of AB.

∴ In ∆ ABQ,

P bisects AQ.

∴ AP = PQ [Converse mid point theorem]

Similarly,

In ∆ DCP,

M is the midpoint of DC.

∴ Q bisects PC.

∴ PQ = QC [Converse mid point theorem]

so,

∴ AP = PQ = QC.

∴ DL and BM trisects diagonal AC.

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@MissSolitary ✌️

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