Question

7^(log (x-3) base 7) + 3(x-4) - 13=0
Solve for x

Answer 1

$heya \\ \\ \\ formulla \: of \: log \: \\ \\ a {}^{ log_{a}(x) } = x \\ \\ \\ \\ 7 {}^{ log_{7}( x - 3) } + 3(x - 4) - 13 = 0 \\ \\ (x - 3) + 3(x - 4) - 13 = 0 \\ \\ x - 3 + 3x - 12 - 13 = 0 \\ \\ 4x = 28 \\ \\ x = 7$

Answer 2

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