Question

7 luggage of mass 10
kg each, fall on a
horizontal conveyor
belt in an airport
moving at 2 m/s in
every
5 seconds.
Power of motor
operating the belt is​

Answer 1

Answer:

6 days ago · 1 answer

7 luggage of mass 10 kg each, fall on a horizontal conveyor belt in an airport moving at 2 m/s in every 5 seconds. Power of motor operating the belt is...

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Answer 2

Answer:

The power of the motor operating the belt is 56 watt

Explanation:

Formula :-

Power (P)= Force (F) × Velocity (t)

Change in momentum in 5 seconds is denoted by Δ P

∴ Force = ΔP / ΔT = $\frac{7 * 10 * 2}{5}$

or, P = $\frac{7 * 10*2*2}{5}$

or, P = $\frac{280}{5}$

or, P = 56 watt.

Therefore, the power of the motor operating the belt is 56 watt