Question

(7 + m)3 expand fast ​

Answer 1

Answer:

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Answer 2

$\implies {(7 + m)}^{3}$

We know that :-

${(a + b)}^{3} = {a}^{3} + {b}^{3} + 3 {a}^{2} b + 3 a{b}^{2}$

Therefore :-

$\implies {(7 + m)}^{3} = {7}^{3} + {m}^{3} + 3 {(7)}^{2} m +( 3 \times 7{m}^{2} )$

we know that :- 7³ = 343 and 7 ² = 49

$\implies {(7 + m)}^{3} = 343 + {m}^{3} + (3 \times 49 m) +21{m}^{2}$

$\implies {(7 + m)}^{3} = 343 + {m}^{3} + 147 m+21{m}^{2}$

Answer :

${m}^{3} + 21{m}^{2} + 147 m+ 343$

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Learn more :-

$\implies{(a+b)^2 = a^2 + b^2 + 2ab}$

$\implies{(a-b)^2 = a^2 + b^2 - 2ab}$

$\implies{(a+b)^3 = a^3 + b^3 + 3ab(a + b)}$

$\implies{(a-b)^3 = a^3 - b^3 - 3ab(a-b)}$

$\implies{(a^3+b^3)= (a+b)(a^2 - ab + b^2)}$

$\implies{(a^3-b^3)= (a-b)(a^2 + ab + b^2)}$