7 men can complete a work in 12 days,after 5 days 2 men were left,in how many days the remaining men complete the same work
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Answer:
9.8 DayS
Step-by-step explanation:
Let’s assume 1 Man does 1 part\day.
Seven men can complete the work in 12 days
TOTAL WORK =7×12= 84 parts
Up to 5 days, all of them worked together
So, work completed =5×7= 35 parts
Remaining work = 49 parts
As 2 men left, so there are 5 men to complete the remaining task.
So, TIME TAKEN =495= 9.8 Day
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