Math, asked by askranveersingh, 10 months ago

7. Mr Gupta was earning 9500 per month till 31st
March 2003 when his salary was raised by 650 per
month. What was the average salary earned by Mr
Gupta in the year 2003?

Answers

Answered by VENOMR
3

Initial Salary for first Three months: 9500/month

Total Salary for first Three months: 9500×3 = ₹28000

Now, Using A.P ,

a= 9500+d = 9500+650= 10150

d= 650

n=9

(Given)

s =  \frac{n}{2} (2a + (n - 1)d

 =  \frac{9}{2} (20300 + 8 \times 650)

 = 4.5(25500)

 = 144750

With Regards from Venom...

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