Question

7 ^ { n - 2 } × 2 ^ { n - 3 } = 56​

Answer 1

Answer:

question is wrong

Step-by-step explanation:

I guess the question is not right but here is the best possible explanation I can get hope it helps you

Answer 2

Answer:

$\left(7n-2\right)\left(2n-3\right)=56\quad :\quad n=\frac{25+5\sqrt{137}}{28},\:n=\frac{25-5\sqrt{137}}{28}$

Step-by-step explanation:

$\left(7n-2\right)\left(2n-3\right)=56$

$14n^2-25n+6=56$

$\mathrm{Subtract\:}56\mathrm{\:from\:both\:sides}$

$14n^2-25n+6-56=56-56$

$14n^2-25n-50=0$

$n_{1,\:2}=\frac{-\left(-25\right)\pm \sqrt{\left(-25\right)^2-4\cdot \:14\left(-50\right)}}{2\cdot \:14}$

$n_{1,\:2}=\frac{-\left(-25\right)\pm \:5\sqrt{137}}{2\cdot \:14}$

$n_1=\frac{-\left(-25\right)+5\sqrt{137}}{2\cdot \:14},\:n_2=\frac{-\left(-25\right)-5\sqrt{137}}{2\cdot \:14}$

$\mathrm{The\:solutions\:to\:the\:quadratic\:equation\:are:}$

$n=\frac{25+5\sqrt{137}}{28},\:n=\frac{25-5\sqrt{137}}{28}$