Math, asked by dhasarathan0831, 2 months ago

7.
Now Sharma age is quarter as old as his father. Six years ago the father's age was seven
times as old as Sharma. Find their present ages
I am not cleared​

Answers

Answered by ggaur507
0

Step-by-step explanation:

Let the present age of the son=x years

Six years ago, the age of the son=x−6 years

Six years ago, the age of the father=7(x−6) years

Present age of the father=7(x−6)+6 years

Six years after, the age of son=x+6 years

Six years after,the age of father=[7(x−6)+6]+6 years

Given: Six years after, the father will be three times as old as his son.

[7(x−6)+6]+6=3(x+6)

⇒7x−42+12=3x+18

⇒7x−3x=18+30

⇒4x=48 or x=

4

48

=12

Present age of the son=x=12years

Present age of the father=7(x−6)+6=7(12−6)+6=7×6+6=42+6=48 years

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