Question

7.Number of moles in 54g of phosphorus (P4
)..
a)0.33
b)0.53
C)0.43 d) 0.49​

Answer 1

Answer:

C = 0.43

Explanation:

number of mols = mass / molar mass

mass = 54 g

molar mass of phosphorous = 30.94

So, if it is P4, 30.94 x 4 = 123.96

n = 54/123.96

n = 0.43

Answer 2

Answer:

The number of moles in $54grams$ of phosphorous $P_{4}$ is $0.435moles$.

Therefore the option (c) is correct.

Explanation:

Given:

Mass of phosphorous $P_{4}=54 grams$

Atomic Mass of phosphorous $=31gmol^{-1}$

Molar mass of $P_{4}=4*31=124gmol^{-1}$

$124g$ of  $P_{4}$ phosphorous $=1mole$

$54g$ of  phosphorous $=\frac{54}{124}=0.435moles$

Therefore the numbers of moles of $P_{4}$ in $54g$  will be equal to $0.435moles$.