7. Of two numbers, 1/5th of the greater is equal to 1/3rd of the smaller and their sum is 16.
The numbers are
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answer is x =10 y=6
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let the no. be x and y
and x be greater and y be smaller one
1/5 of x =1/3 of y
and x+y =16
x =16- y
so putting the above value of x
1/5×16 - y =1/3 ×y
16-y/5 = y/3
by cross multiplication method
3(16-y)= 5y
48-3y =5y
48 =5y + 3y
48 = 8y
y = 6
so x = 16 - y
putting value of y in this
x = 16-6
x =10
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